Re: [xml-dev] XML Schema - How to define any element of type Foe
Hi Christophe,
Here's some idea based on XSD 1.1 assertions.<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:complexType name="parent">
<xs:sequence>
<xs:any processContents="skip"/>
</xs:sequence>
<xs:assert test="*/not(node())"/>
<xs:assert test="count(*/@*) eq 2"/>
<xs:assert test="*/xs:positiveInteger(@end) ge */xs:positiveInteger(@start)"/>
</xs:complexType>
<xs:element name="X" type="parent"/>
</xs:schema>
You won't need an explicit complex type definition named "Foe".
<?xml version="1.0" encoding="UTF-8"?>
<X>
<A end="2" start="1"/>
</X>
On 9 March 2017 at 14:37, <[email protected]> wrote:
Hello,
I have a complexType definition, Foe.
In another complexType, I want to allow any child element, but require that each child element is valid against Foe definition.
Something like :
<xs:complexType name="Foe">
<xs:attribute name="start" type="xs:positiveInteger" use="required"/>
<xs:attribute name="end" type="xs:positiveInteger" use="required"/>
<xs:assert test="@end ge @start">
</xs:complexType>
<xs:complexType name="parent">
<xs:sequence>
<xs:any type="Foe"/>
</xs:sequence>
</xs:complexType>
How can I do this ?
Thanks,
Christophe
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Regards,
Mukul Gandhi